x^2-3x-4.75=0

Solution for x^2-3x-4.75=0 equation:

x^2-3x-4.75=0

a = 1; b = -3; c = -4.75;
Δ = b2-4ac
Δ = -32-4·1·(-4.75)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-2\sqrt{7}}{2*1}=\frac{3-2\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+2\sqrt{7}}{2*1}=\frac{3+2\sqrt{7}}{2}
$